22 Years' Battery Customization

How to calculate the battery capacity working time

APR 09, 2019   Pageview:516

Calculation method of battery capacity (C):

 

Capacity C = discharge battery (constant current) I × discharge time (hours) T

 

In turn:

 

Discharge time T = capacity C / discharge current (constant current) I

 

For example, if a battery is discharged with a constant current of 500MA (mA) for 2 hours, then the capacity of this battery is equal to 500MA*2H=1000MAH=1AH.

 

If a battery is discharged for 2 hours with a current of 5 amps, then the capacity of the battery is 10 AH.

 

Second question: I think you want to ask what is the voltage difference between the full battery and the discharge?

 

In fact, this is related to the type and type of battery. Different types of batteries are different. For example, lithium batteries for mobile phones, rated voltage 3.6, minimum voltage 3V, lead-acid battery single-cell rated voltage is 2V, minimum power 1.75V if it is 12V The lead-acid battery is rated at 12V and has a minimum voltage of 10.5V.

 

At present, the pension after retirement is composed of basic pension + personal account pension (participating in the pension insurance system before the work, as well as transitional pension).

 

The calculation method is as follows

 

First, the basic pension = (the average monthly salary of the employees in the province in the previous year when the insured is retired + the average monthly payment of the indexed monthly income) / 2 × payment period × 1%. (Note: I am exponentially monthly average payment wage = the average monthly salary of employees in the province last year × my average contribution index).

 

Second, personal account pension = personal account storage amount of the number of months (50 for 195, 55 for 170, and 60 for 60).

 

2

 

How to calculate battery working time

 

A 220mah 3V lithium battery, working at a working voltage of 3V is 1.2mA, how long does it work on the appliance?

 

Answer:

 

Here 220mAh is the total amount of electricity discharged Q=It

 

So t=Q/I=220/1.2=183h. It can be used for 183 hours under standard conditions.

 

NOTE: 3V in the title is the voltage for normal operation.

 

Ps:

 

The working time of the battery is estimated based on the capacity of the battery and the operating current, because the calculated time must be longer than the actual use time, because the battery discharge process is a nonlinear change, especially at the end of the discharge, the storage capacity of the battery is less, the faster the discharge, the shorter the use time. The specific estimation method is:

 

Estimated time = capacity (Ah) / maximum discharge current (A)

 

For example, the battery is Ah (Ah), the current of the appliance is 2A, 20/2 = 10 hours. About 10 hours of work

 

Note: The battery capacity is large, and the discharge current is large. The general capacity is in unit Ah and the current is indicated by A.

 

1. “mAh” is the unit of battery capacity. When the Chinese name is mAh (when measuring large-capacity batteries such as lead storage batteries, for the sake of convenience, it is generally indicated by “Ah”, the Chinese name is Anshi).

 

1mAh = 0.001 amps * 3600 seconds = 3.6 amp seconds = 3.6 coulombs

 

2. Coulomb is the unit of electricity. Coulomb is not the basic unit of the International System of Units, but the unit of export of the International System of Units. 1 coulomb = 1 ampere per second.

 

The amount of 1A current transported in 1s, ie 1C = 1A·s.

 

3. Power electric power calculation formula: P=UI. The unit of P is watt W; in the purely resistive circuit, according to Ohm's law U=IR, it can also be obtained by substituting P=UI: P=I*IR=(U*U)/R

 

First, the most direct algorithm:

 

1, first get the current of the electrical equipment

 

2. Dividing the battery capacity by the current of the powered device is the length of time that can be used.

 

E.g:

 

A 3000mAH, rated voltage 5V battery is powered by a 2.5W, 5V power supply. Its theoretical duration is:

 

I=P/U=>2.5w/5v=>0.5A=>500MA

 

3000mAh, that is, 3000MA current can be discharged for one hour.

 

3000/500=6 hours

 

Second, the charge amount Coulomb algorithm

 

C=IS=>3A*3600s=>10800c Coulomb (charge amount)

 

10800c*5v=54000w electric energy

 

54000w/2.5w=21600/3600s=6h

 

The page contains the contents of the machine translation.

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